3n^2-1n-92=0

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Solution for 3n^2-1n-92=0 equation:



3n^2-1n-92=0
a = 3; b = -1; c = -92;
Δ = b2-4ac
Δ = -12-4·3·(-92)
Δ = 1105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{1105}}{2*3}=\frac{1-\sqrt{1105}}{6} $
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{1105}}{2*3}=\frac{1+\sqrt{1105}}{6} $

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